We now look at the case of non-Linear Alfven waves derived from two- fluid equations:
1) Continuity equation: ¶ / ¶x (ns, Vs ) = 0
2) Momentum eqn. Vs
¶ / ¶x (Vs ) = qs, / ms (E + v x B)
Vs ¶ Vs / ¶x = qs, //ms [E + V x B]
3) ¶ / ¶x (B) = 4 p å qs, Vs
n s,
4) ¶ / ¶x · (B) = 0
(5) ¶ / ¶x · (E) = 4 p å qs, n
s,
We consider first the solution in 1-dimension.
Choosing the field to have a geometry such that:
B = [ B 0 , B y (x), B z (x)]
And: E = (E(x), 0 , 0)
Vs = [Us (x), Vs (x) , Ws (x)]
Assuming exact neutrality: n i (x) = n e (x) = N(x)
But: ¶ E / ¶x = 0 So no E
We have then:
(i) ¶ (ns, U s ) / ¶x = 0 so: ns U s = const. (Or: Ñ · J = 0 )
(ii) m s U s (d U s / dx) = qs, (Vs B z - Ws B y )
(iii) m s U s (d V s / dx) = qs, (Ws B 0 - Us B z )
(iv) m s U s (d W s / dx) = qs, (Us
B y - Vs B 0 )
Further: Ui = U e
dB y / dx = 4 p å qs, Ws
n s
dB z / dx = - 4 p å qs, Vs
n s
Now multiply:
å ns by Eqn. (ii)
Þ F å ms (d U s / dx)
= å n s qs, Vs
B z - å n s qs, Ws B y
Then:
F m z (dU / dx)
= - 1/4 p
B
z (d B z / dx) - 1/4 p B
y (d By / dx)
Þ d / dx (F U ) = - 1/8 p d/dx (B
z 2 + By 2 )
F U + (B
z 2 + By 2 ) /8 p = const.
= P
Where the first term on the left is the ram
pressure and the 2nd term is the magnetic pressure.
To be continued...
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