Question -
Answer:
G, the Newtonian gravitational constant is G = 6.7 x 10-11 Nm2/ kg2
The mass of the Earth is 6 x 1024 kg
Then:
[2MG/ r]1/2 = [2 (6 x 1024 kg) (6.7 x 10-11 Nm2/ kg2)/ 6.4 x 106 m ]1/2
Now consider a satellite already in orbit around Earth. Why doesn't it just fall? Well, firstly because it is moving too rapidly to do so. The speed of the satellite with respect to Earth ensures it will stay in orbit. What does this mean?
it has NO vertical or downward velocity . The reason is that it falls
from each position at the same rate the Earth's surface falls away
underneath it. Basically, the inward directed force Fc keeps the
Perhaps a better diagram to convey the falling, from successive tangents, T, T' T"' etc is shown below:
Thus we see the gravitational force of attraction (based on Newton's law of gravitation, e.g. F = GMm/ r 2) is what supplies the centripetal force to keep the object in orbit. This condition of perpetual free fall is what we mean by "being in orbit".
The same applies to other bodies orbiting larger ones. Thus, a planet
orbiting the Sun is also in a similar state of free fall, with respect to
the surface of the Sun. By the same token its gravitational force of
While it is being pulled in toward the Sun (by the Sun's gravity) it has a speed in its orbit large enough so there's no vertical (e.g. downward) velocity component.

where r is the radius vector at the point, and T is the period.
VP = h/ a(1 - e)
where a is the semi-major axis, and e is the eccentricity.
For the velocity at aphelion:
VA = h/ a (1 + e)
(VP/VA) = (1 + e)/ (1 - e)
In the same exact fashion, the Moon (in its own elliptical orbit) orbits the Earth (free fall) rather than 'crashing down' into it, because the speed of the Moon in its orbit is large enough to overcome the inward pull of Earth gravity. The Moon keeps continually falling in its orbit relative to the Earth - marking out an elliptical orbit- rather than falling ONTO the Earth.
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