P = G r Mr/ V r
We have: U = 2.006 and V = 2.829
Mr/M = 0.395 = 1.568 x 1033 g
density:  log (rho) =  log   r 
r = UMr/4p r3
r = UMr/4p r3
= [(2.006) (1.568 x 1033 g)]/ 4p (2.567 x 1010 cm) 3
r  =   14.80  g/ cm 3        log   r  = 1. 1703
Pressure:
P   =      G  r Mr/ V r
=  [(6.67 x  10-8 dyne-cm 2/ g.2)  (14.80  g/ cm 3 )(1.568  x 1033  g)/   (2.829)(2.567  x 1010  cm)
P   =  2.131  x 1016    dyne/ cm 2
log P   =   16.3286
 
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