Express p =
[1 2 3 4]
[2 3 1 4]
as the product of transpositions, and determine the sign (+1 or -1) of the resulting end permutation.
Solution:
Let T1 be the transposition 2 <-> 1 leaving 3, 4 fixed, so:
T1 p =
[1 2 3 4]
[1 3 2 4]
Let T2 be the transposition 2 <-> 3 leaving 1, 4 fixed, so:
T2 T1 p =
[1 2 3 4]
[1 2 3 4]
Then:
T2 T1 p = I (identity)
TWO transpositions (T1, T2) operated on p, so that the sign of the resulting permutation (to reach identity) is +1. The permutation is therefore even.
T1 p =
[1 2 3 4]
[1 3 2 4]
Let T2 be the transposition 2 <-> 3 leaving 1, 4 fixed, so:
T2 T1 p =
[1 2 3 4]
[1 2 3 4]
Then:
T2 T1 p = I (identity)
TWO transpositions (T1, T2) operated on p, so that the sign of the resulting permutation (to reach identity) is +1. The permutation is therefore even.
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