As many readers would have seen by now, linear algebra often plays a role in assorted formulations of physics, including modern physics. Two of the more important aspects are unitary and Hermitian matrices (which applications will be covered in a future blog).
Basically, a square matrix (one with the same number of rows and columns) is called Hermitian if it has complex numbers, and if:
A = A*
i.e. the matrix is found equal to its conjugate transpose. We already saw how to obtain the transpose of a matrix for normal, non-complex matrices, e.g. if X=
(-1.....2)
(-2.....3)
Then: t^(X) =
(-1.....-2)
(2.......3)
Now, we need to reckon in the conjugate transpose such that: A* = t^(A') (Which we will soon see in some examples). Meanwhile, we say a matrix is unitary if:
A^-1 = A*
i.e. if the inverse of the matrix is equal to its conjugate transpose. This also implies that we have:
A A* = A* A = I
where I denotes the identity matrix. For example, for a 2 x 2 matrix, I =
(1...0)
(0....1)
Example: Show that the matrix M =
(2.....i)
(-i....5)
is Hermitian
We first get the complex conjugate of the matrix or, M' =
(2.....-i)
(i......5)
Then we obtain the transpose of that, or M* = t^(M') =
(2.....i)
(-i......5)
and since M = M* = t^(M')
the matrix is Hermitian.
Example (2). Show that the matrix A =
(cos Θ ..... sin Θ)
(-sin Θ ..... cos Θ)
is a unitary matrix.
By definition, the matrix A (a real matrix, not complex) will be unitary if: A ( t^A) = 1
We note that the transpose t^A =
(cos Θ ..... -sin Θ)
(sin Θ ..... cos Θ)
and: A (t^A) =
(cos Θ ..... sin Θ) (cos Θ ..... -sin Θ)
(-sin Θ ..... cos Θ)(sin Θ ..... cos Θ)
= 1
Hence, the matrix is unitary.
Problems:
1) Show that the matrix M =
(1 + i.....2)
(2..........5i)
is not Hermitian
2) Determine whether the matrix Y =
(1.....(1+ 1i).......5)
((1- i).......2... ...i)
(5..........-i...........7)
is Hermitian or not.
3) Determine whether the matrix, X =
(-i...1)
(1.....i)
is unitary or not.
4) Let A and B be 2 x 2 Hermitian matrices. Show that (A + B) is Hermitian.
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