Monday, October 28, 2013

Looking at Harmonic Conjugates and the Cauchy- Riemann Equations


A useful theorem when looking at the Cauchy –Riemann equations is the following:

 
A function f(z) = u(x,y) + iv(x,y) is analytic in a domain D if and only if v is a harmonic conjugate of u.

 
Consider the function we saw already in the  Oct. 7 blog:


f(z) = u(x,y) + iv(x,y) =  (x2 – y2) + i2xy

 
So that: u(x,y) =  (x2 – y2)     and: v(x,y) =  2x y

 
Now, we first check to see if the eqns. are analytic

 
Take u/ x    =   2x

 
And:  v/ y    =   2x

 
Since:  u/ x  =  v/ y     then u(x.y) is analytic

 
Now check the other function, v(x.y)

 
v/ x  =  2y


And:  -  u/ y   =  - (-2y) = 2y

 
So that -  u/ y  =    v/ x   and hence  v(x,y) is analytic..

 
Note: If f(z) is analytic everywhere in the complex plane it is said to be an entire function.

 

Now, to see if it's a harmonic conjugate, switch u(x,y) with
   v(x,y) so that:

 
f(z) = u(x,y) + iv(x,y) =   2xy  + i(x2 – y2)

 
u(x,y) = 2xy and v(x,y) =  (x2 – y2)

 
We first check to see if the u, v functions are analytic

 
Take u/ x    =   2y

 
And:  v/ y    =   - 2y

 
Since:  u/ x  =    v/ y    


Thus, it holds only where y = 0,  so then f(x) is differentiable only for points that lie on the x –axis and we conclude the function reversed for conjugates is nowhere analytic. The conclusion is thus that while v is a harmonic conjugate of u throughout the  z-plane, v is not a harmonic conjugate of u.

 
In general, and based on this, one is led to conclude that given a function:


f(z) = u(x,y) + iv(x,y)

 
then f(z) is analytic in some domain D if and only if (-if(z) = v(x,y) –iu(x,y) is also analytic there


Example (2):   Let f(z) = 3x + y + i(3y – x)

 
Show that v is a harmonic conjugate of u and hence the function is analytic in a domain D when u and v are interchanged for f(z). Is the  function also entire?


We have u(x,y) = 3x + y and v(x,y) = (3y – x)

 
Check Cauchy relations:


Take u/ x    =   3

 
And:  v/ y    =   3


Since:  u/ x  =  v/ y     then u(x.y) is analytic

 
Now check the other function, v(x.y):

 
v/ x  =  -1

 
And:  -  u/ y   =  - (1) = -1

 
So that -  u/ y  =    v/ x   and hence  v(x,y) is analytic..


Now, interchange u(x,y) with v(x,y):

 
f(z) = 3x -  y +  i(3y +  x)

 
We have u(x,y) = 3x - y and v(x,y) = (3y +  x)

 
Check Cauchy relations:

 
Take u/ x    =   v/  y 

 
And:  v/ y    =   3  =  u/ x

 
Since:  u/ x  =  v/ y     then u(x.y) is analytic


Now check the other function, v(x.y):


v/ x  =  +1


And:  -  u/ y   =  - (-1) =  +1

 
So that -  u/ y  =    v/ x   and hence  v(x,y) is analytic..

 
Since v is a harmonic conjugate of u then the function is analytic in a domain D when u and v are interchanged.

If the function is entire then it also satisfies the LaPlace equation: Ñ 2u = 0

 
Then:


2 u/ x2  +  2 u/ y2       = 0 + 0 = 0

 
And: 

 
2 v/ x2  +  2 v/ y2    =  0 + 0 = 0

 
So the function is also entire on the complex plane.


Problems for the Math Maven:

 
1) Given the function:


f(z) = u(x,y) + iv(x,y) =  cos x cosh y – i(sinx sinh y)

 
a)     Verify the Cauchy-Riemann equations are satisfied

b)     Are they also satisfied for the harmonic conjugate, i.e. when u and v are interchanged?


2)     Let u(x,y) =  (x2 – y2) +  2x

 
a)     Show u(x,y) is a harmonic function

b)     Hence or otherwise, find the harmonic conjugate v(x,y) of u.