A function f(z) = u(x,y) + iv(x,y) is analytic in a domain D if and only if v is a harmonic conjugate of u.
Consider the function:
f(z) = u(x,y) + iv(x,y) = (x2 – y2) + i2xy
Now, we first check to see if the eqns. are analytic
Take ¶ u/ ¶ x = 2x
And: ¶ v/ ¶ y = 2x
Since: ¶ u/ ¶ x = ¶ v/ ¶ y then u(x.y) is analytic
Now check the other function, v(x.y)
¶ v/ ¶ x = 2y
And: - ¶ u/ ¶ y = - (-2y) = 2y
So that - ¶ u/ ¶ y = ¶ v/ ¶ x and hence v(x,y) is analytic..
Note: If f(z) is analytic everywhere in the complex plane it is said to be an entire function.
Now, to see if it's a harmonic conjugate, switch u(x,y) with v(x,y) so that:
f(z) = u(x,y) + iv(x,y) = 2xy + i(x2 – y2)
u(x,y) = 2xy and v(x,y) = (x2 – y2)
We first check to see if the u, v functions are analytic
Take ¶ u/ ¶ x = 2y
And: ¶ v/ ¶ y = - 2y
Since: ¶ u/ ¶ x = ¶ v/ ¶ y
Thus, it holds only where y = 0, so then f(x) is differentiable only for points that lie on the x –axis and we conclude the function reversed for conjugates is nowhere analytic. The conclusion is thus that while v is a harmonic conjugate of u throughout the z-plane, v is not a harmonic conjugate of u.
In general, and based on this, one is led to conclude that given a function:
f(z) = u(x,y) + iv(x,y)
then f(z) is analytic in some domain D if and only if (-if(z) = v(x,y) –iu(x,y) is also analytic there
Example (2): Let f(z) = 3x + y + i(3y – x)
Show that v is a harmonic conjugate of u and hence the function is analytic in a domain D when u and v are interchanged for f(z). Is the function also entire?
We have u(x,y) = 3x + y and v(x,y) = (3y – x)
Check Cauchy relations:
Take ¶ u/ ¶ x = 3
And: ¶ v/ ¶ y = 3
Since: ¶ u/ ¶ x = ¶ v/ ¶ y then u(x.y) is analytic
Now check the other function, v(x.y):
¶ v/ ¶ x = -1
And: - ¶ u/ ¶ y = - (1) = -1
So that - ¶ u/ ¶ y = ¶ v/ ¶ x and hence v(x,y) is analytic..
Now, interchange u(x,y) with v(x,y):
f(z) = 3x - y + i(3y + x)
We have u(x,y) = 3x - y and v(x,y) = (3y + x)
Check the Cauchy relations:
Take ¶ u/ ¶ x = ¶ v/ ¶ y
And: ¶ v/ ¶ y = 3 = ¶ u/ ¶ x
Since: ¶ u/ ¶ x = ¶ v/ ¶ y then u(x.y) is analytic
Now check the other function, v(x.y):
¶ v/ ¶ x = +1
And: - ¶ u/ ¶ y = - (-1) = +1
So that - ¶ u/ ¶ y = ¶ v/ ¶ x and hence v(x,y) is analytic..
Since v is a harmonic conjugate of u then the function is analytic in a domain D when u and v are interchanged.
If the function is entire then it also satisfies the LaPlace equation: Ñ 2u = 0
Then:
¶ 2 u/ ¶ x2 + ¶ 2 u/ ¶ y2 = 0 + 0 = 0
And:
¶ 2 v/ ¶ x2 + ¶ 2 v/ ¶ y2 = 0 + 0 = 0
So the function is also entire on the complex plane.
Practice Problems:
1) Given the function:
f(z) = u(x,y) + iv(x,y) = cos x cosh y – i(sinx sinh y)
a) Verify the Cauchy-Riemann equations are satisfied
b) Are they also satisfied for the harmonic conjugate, i.e. when u and v are interchanged?
2) Let u(x,y) = (x2 – y2) + 2x
a) Show u(x,y) is a harmonic function
b) Hence or otherwise, find the harmonic conjugate v(x,y) of u.
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