P = G r Mr/ V r
We have: U = 2.006 and V = 2.829
Mr/M = 0.395 = 1.568 x 1033 g
density: log (rho) = log r
r = UMr/4p r3
r = UMr/4p r3
= [(2.006) (1.568 x 1033 g)]/ 4p (2.567 x 1010 cm) 3
r = 14.80 g/ cm 3 log r = 1. 1703
Pressure:
P = G r Mr/ V r
= [(6.67 x 10-8 dyne-cm 2/ g.2) (14.80 g/ cm 3 )(1.568 x 1033 g)/ (2.829)(2.567 x 1010 cm)
P = 2.131 x 1016 dyne/ cm 2
log P = 16.3286
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