In an earlier blog we examined the fascinating mathematical structures called groups. We recall here the properties that make a group, from the definition given:
A GROUP is a set G with one binary operation defined on it , and G satisfies the axioms:
a) Associative law: a· (b · c) = (a· b) · c
b) Identity element (e): there exists an element e in G such that: e · a = a for all a in G and a · e = a
c) Inverse element: For any a in G there exists an element a^-1 in G such that:
a · a^-1 = a^-1 · a = e
There was also the additional property that defined an Abelian Group:
d) Only if there exists elements a, b in G such that (a · b) = (b · a), then G is said to be an Abelian Group. (Commutative property).
We now want to see how these apply to groups that are posed in matrix form.
A matrix is an assembly of numerical quantities in the form:
(a11 a12)
(a21 a22)
Matrix multiplication, the main operation we will need to know, is easily obtained.
I.e. say the above matrix is denoted A, and another B =
(b11 b12)
(b21 b22)
then A X B =
(a11 a12) (b11 b12)
(a21 a22) (b21 b22)
= [{(a11b11) + (a12b21)} --{(a11 b12)+ (a12 b22)} ]
[(a21b11) + (a22b21) } --{((a21 b12) + (a22 b22)}]
For example, let A=
(1 2)
(1 2)
and B =
(1 3)
(2 2)
then A x B=
(5 7)
(5 7)
The reader is invited to verify this for himself.
We are now in a position to look at some simple 2 x 2 matrix groups, and also assess whether they're Abelian or not.
One example is the special unitary group, SU2. The elements of SU2 are the unitary 2 x 2 matrices with Det = 1 (determinant). [Note: the determinant is taken as follows, using the elements of matrix A, for which Det [A] = (a11 x a22) - (a12 x a21), thus Det [A] = 2 - 2 = 0.]
The elements are shown in their standard matrix form in Fig. 1, and the reader should easily be able to verify that the elements form a group. I tcan be seen, for example, that: II= J*J= J^2 = K*K = K^2 = -i, and IIJ = -JII = K.
Another interesting group is PSL(2, z) which has generators:
s =
(0 1)
(-1 0)
and
t =
(0 -1)
(1 - 1)
Yet another group with 2 x 2 matrix elements is sl(2) which has elements: h, e and f such that:
h =
(1 0)
(0 -1)
e (identity element) =
(0 1)
(0 0)
f =
(0 0)
(1 0)
The elements of the group can easily be shown to obey the relations:
[h, e] = h*e - e*h = 2e, [h.f] = h*f - f*h = -2f, and [e,f] = e*f - f*e = h
(understanding that matrix subtraction simply follows the rule, e.g. :
[A] - [B]
=
{(a11 - b11) (a12 - b12)}
{(a21 - b21) (a22 - b22)}
using the designated elements assigned earlier for the generic matrices A, B)
For the already identified matrices A and B, [A] - [B] =
(0 -1)
(-1 0)
Then there is the famous Klein Viergruppe with members: e (identity), a, b and c. The 2 x 2 matrix members are shown in Fig. 2 along with 4 different operations.
The ambitious reader can gain further insights via the following exercises!
Practice Problems:
1. For the group PSL(2,z) show that the identity element (e) = s^4 = t^3.
2. For the group sl(2) show that:
(a) [h.f] = h*f - f*h = -2f
(b) The "Casimir element", C, of sl(2) is defined according to:
h^2/ 2 + h + 2f*e
find the element
3. Show that the Klein Viergruppe, V4, is Abelian.
A GROUP is a set G with one binary operation defined on it , and G satisfies the axioms:
a) Associative law: a· (b · c) = (a· b) · c
b) Identity element (e): there exists an element e in G such that: e · a = a for all a in G and a · e = a
c) Inverse element: For any a in G there exists an element a^-1 in G such that:
a · a^-1 = a^-1 · a = e
There was also the additional property that defined an Abelian Group:
d) Only if there exists elements a, b in G such that (a · b) = (b · a), then G is said to be an Abelian Group. (Commutative property).
We now want to see how these apply to groups that are posed in matrix form.
A matrix is an assembly of numerical quantities in the form:
(a11 a12)
(a21 a22)
Matrix multiplication, the main operation we will need to know, is easily obtained.
I.e. say the above matrix is denoted A, and another B =
(b11 b12)
(b21 b22)
then A X B =
(a11 a12) (b11 b12)
(a21 a22) (b21 b22)
= [{(a11b11) + (a12b21)} --{(a11 b12)+ (a12 b22)} ]
[(a21b11) + (a22b21) } --{((a21 b12) + (a22 b22)}]
For example, let A=
(1 2)
(1 2)
and B =
(1 3)
(2 2)
then A x B=
(5 7)
(5 7)
The reader is invited to verify this for himself.
We are now in a position to look at some simple 2 x 2 matrix groups, and also assess whether they're Abelian or not.
One example is the special unitary group, SU2. The elements of SU2 are the unitary 2 x 2 matrices with Det = 1 (determinant). [Note: the determinant is taken as follows, using the elements of matrix A, for which Det [A] = (a11 x a22) - (a12 x a21), thus Det [A] = 2 - 2 = 0.]
The elements are shown in their standard matrix form in Fig. 1, and the reader should easily be able to verify that the elements form a group. I tcan be seen, for example, that: II= J*J= J^2 = K*K = K^2 = -i, and IIJ = -JII = K.
Another interesting group is PSL(2, z) which has generators:
s =
(0 1)
(-1 0)
and
t =
(0 -1)
(1 - 1)
Yet another group with 2 x 2 matrix elements is sl(2) which has elements: h, e and f such that:
h =
(1 0)
(0 -1)
e (identity element) =
(0 1)
(0 0)
f =
(0 0)
(1 0)
The elements of the group can easily be shown to obey the relations:
[h, e] = h*e - e*h = 2e, [h.f] = h*f - f*h = -2f, and [e,f] = e*f - f*e = h
(understanding that matrix subtraction simply follows the rule, e.g. :
[A] - [B]
=
{(a11 - b11) (a12 - b12)}
{(a21 - b21) (a22 - b22)}
using the designated elements assigned earlier for the generic matrices A, B)
For the already identified matrices A and B, [A] - [B] =
(0 -1)
(-1 0)
Then there is the famous Klein Viergruppe with members: e (identity), a, b and c. The 2 x 2 matrix members are shown in Fig. 2 along with 4 different operations.
The ambitious reader can gain further insights via the following exercises!
Practice Problems:
1. For the group PSL(2,z) show that the identity element (e) = s^4 = t^3.
2. For the group sl(2) show that:
(a) [h.f] = h*f - f*h = -2f
(b) The "Casimir element", C, of sl(2) is defined according to:
h^2/ 2 + h + 2f*e
find the element
3. Show that the Klein Viergruppe, V4, is Abelian.
Solutions to be given in a future blog!
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