The Problems:
1. (a)Write the phase space dimension for a 3-particle system.
(b) Write out the number density for this system.
Solutions:
a) We need the phase space formula: 6No - D where No is the number of particles in the system. In this case No = 3, so:
6No - D = 6 (3) -D or 18 dimensions
b) The number density for the system is:
N( Xi.... Xn ,Vi ....Vn ) = å No i=1 d (Xi - Xi (t)) d (Vi - Vi (t))
Where No = 3, so:
N( X1, X2 , X3 ,V1 , V2., V3 ) =
d (X1 - X1 (t)) d (V1 - V1 (t))d (X2 - X2 (t)) d (V2 - V2 (t)) d (X3 - X3 (t)) d (V3 - V3 (t)
2. We saw (x1, v1) = ( x1 , y1 , z1, vxi, vyi, vzi) is a 6-dimensional phase space. What would be the number of dimensions for the 12-D phase space:
(x1, v1, x2, v2 )?
Write them all out in a bracket.
Solution:
(x1, v1, x2, v2 ) = ( x1 , y1 , z1, vxi, vyi, vzi, x2 , y2 , z2, vx2, vy2, vz2,)
3. Show how V'i = q/ m [ E (Xi ) + Vi x B( Xi )
translates to Newton's 2nd law of motion.
(Hint: You need to incorporate the Lorentz force.)
Answer:
Given the nature of the plasma, charged particles of the system moving in magnetic field (B) the Lorentz force is:
F = q ( E + v x B)
Or, in terms of Newton's 2nd law:
m (dv/dt) = ma = q ( E + v x B)
Or, to conform with the plasma expression:
V'i = q/ m ( E + v x B)
Where: E = E (Xi ) and: v x B = Vi x B( Xi )
Where the Xi are position dependent in the coordinate system.
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