Problem:
For each of the frequency solutions (h 1 etc. )applied to the linear tri-atomic molecule, give the relation between the normalized amplitudes: A1, A2 and A3 and the angular frequency.
Solution:
The three solutions for the angular frequency were already given in the Aug. 18 blog post, from the secular determinant:
(k - w 2 m …-k… . .0)
(-k …..2 k - w 2 m .. -k)
(0…. ….-k….. k - w 2 m)
I.e.
w1 = 0, w2 = Ö(k/ m), w3 = Ö{ k/ m (1 + 2m/ M)}
The amplitudes from these solutions are then obtained (as shown in the post) from the Lagrange tensor:
h 1 = A1 exp (iw t)
h 2 = A2 exp (iw t)
h 3 = A3 exp (iw t)
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