Curves in 3-Space
As previously defined, every point in the
space R 3 is uniquely determined by a position
vector x = (x1 ,  x2 , x3). 
Then in order to introduce the concept of a curve we use a real vector
function: x =  x(t)  and this will have components:
x1 =  x1 (t) 
    x2 =  x2 (t) 
    x3 =  x3 (t)
Which are single-valued functions of  real variable t
defined in the interval:   I :   a  < 
t  <   b.  To every value of t a point
of R 3  is associated whose position vector is
x(t).
Then the vector function determines a point
set M in R 3   which we call a parametric
representation of the set M, and the variable t is called the parameter of the
representation. Given the above and that the trivial case of M = 1 point is
discarded while the vector function must have multiple derivatives, we may
assume:
1)  The functions xi =  xi (t) (i=1,2,3.....) 
are  r (> 1) times continuously differentiable in I where
the value of r will depend on the problem under consideration.
2) For every value of t in I, at least one of the
three functions:
xi (t) =   d xi (t)/
dt
is different from zero.
Definition: Arc
of a curve:
A point set in space  R 3 
which can be represented by the allowable representations of an equivalence
class is called an arc of a curve.  The functional correspondence of the
points of an arc to the value of t- given by an allowable representation x =
x(t) is continuous.   
 If an arc is simple the correspondence between the
points and the values of the parameter t is one to one.  In this case not
only is the functional relation of the points to the values of t continuous but
also the inverse relation, i.e. the relation of the values of t to the points.
Definition:  curve:
A point set is called a curve if it can be represented by
an equivalence class of the form x = x(t) whose interval I is not assumed to be
closed or bounded, but is such that one always obtains the arc of a curve if
the values of the parameter t are restricted to any closed and bounded
subinterval of I.  
A curve is said to be closed if it possesses at least one
representation which is periodic, i.e. of the form:  
x(t  +  w  ) =  x(t)
Thus the circle:  x(t) =  (r cos t, r
sin t, 0)  with  r 2 
=  4  is an  example of a
simple closed curve.  
We have: x1 = r cos t ,  x 2 = r sin t,  x 3  = 0
->  x 1 2    +    x 2 2  =   r 2 (cos 2 t   + 
 sin 2 t) =  4
So,
the circle is closed and in the x 1 x 2 -plane, e.g.

Special curves:  A few special curves and their representations are now
examined.  The main proviso here is to point out that there are curves of
the form  x =  x(t)  that
cannot always be represented as a whole in the forms:   x 2  =  x 2  (x 1),   x 3  = 
x 3  (x 1).  
This difficulty will occur when one value of
the independent variable corresponds to several values of the dependent one,
since the concept of a function requires a 1:1 onto correspondence of dependent
to independent variable. Thus, in the case of the circle, a representation of
the form just highlighted would be:
x 2  = + Ö( r 2  
-   x 1 22)      x 3  = 0
If we choose the + sign, we have a semicircle in the upper
half plane. If we choose the negative sign we have a semicircle in the other
half plane.
Ellipse with center
at origin of coordinate system in space.  In the parametric representation
we can write (analogous to that for the circle):  x(t) =  (a cos t, b sin t, 0)  
Or:
x 1 2 / a 2 +    x 2 2  / b 2 =
1,   x 3  =
0
If the principal axes have lengths 2a and 2b (say with a = 4, b = Ö8), respectively and coincide with the x 1 and x 2 axes, respectively, we obtain the graph shown below:
Note that if a= b = r we just recover a
circle:
 x(t) =  (r
cos t, r sin t, 0)
The folium of Descartes:  
This can be expressed in parametric form as:  
 x(t) =  (3t/
1 +  t3 ,  3t2/ 1 +  t3  ,
0)  
This curve will be found to lie in the 1st, 2nd and 4th quadrant of the x 1 - x 2 plane as shown below:
By inspection the reader will also see it has
a double point at (x 1 ,  x 2) = (0, 0) .  Note also that part of the
curve in the 2nd quadrant corresponds to values of t from -1 to 0, while the
loop in the first quadrant corresponds to values between 0 and  ¥.  In the 4th quadrant the t-values range from - ¥  to  -1.
The circular helix:  
The parametric form here is:  
x(t) =  (r cos t, r sin t, ct)   c ≠ 0.  
The orthogonal projection of the helix into the 
 x 1 x 2 - plane, e.g.
is the circle: 
x 1 2 
+ x 2 2    
-  r 2  = 0,  x 3  = 0
which is the intersection of this plane with
the cylinder of revolution on which the helix lies. Projecting the helix
orthogonally into the x2 x 3 - plane we obtain the sine curve:
 x2 - r sin (x 3  /c)  = 0,  x 2 = 0
A cosine curve will be obtained by projecting the helix
orthogonally into the x 1 x 2  - plane.
Suggested Problems:
1) Sketch the graphs of;
x 2  = - Ö( 8 2   -   x 1 2)
And:
x 2  = - Ö( 16 2   -   x 1 2)
On the same Cartesian axes.
2)(a) Write the polar form of the equation of the line:
3 x 1   +   4 x 2   =  5
b)Determine the polar (r,  q) equation for :
x 1 2 
+ x 2 2   -  2ax 2  = 
0,    a  ≠   0
And sketch the resulting curve.




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