Friday, September 4, 2026

Reviewing Algebra II: Solutions To Simplifying & Solving Exponential Equations

Solve each equation for the unknown and check:

 (1) 2a-3 - 1 = 15

Solution:  Isolate exponent side:
2a-3  = 16

Divide each side by 2:

a-3  = 8

Get both sides to same base:

a-3  = 8 =   2-3

a =  2

Check in original eqn. 2a-3 - 1 = 15

2(2)-3 - 1 = 15 =  2 (8) - 1 = 15

16  - 1  = 15 


(2) 9x =  55

Solution:  

Use the power rule: i.e. ln b  = x ln b, to bring the variable exponent (x) to the front, i.e.

x ln 9 =  ln 55

Solve by dividing both sides by ln 9:

x  =   ln 55/ ln 9

x =  4.007/ 2.197

x = 1.824

Check in original eqn.  x ln 9 =  ln 55

(1.824) ln 9  =   ln 55

(1.824) (2,197)  = 4.007  


3) 5x1/2 + 7   = 22

Solution: Isolate exponent side:

5x1/2    = 15

Divide both sides by 5:

x1/2    = 3

Ö x  =   3

x =   9

Check in original eqn. 5x1/2 + 7   = 22

5x1/2 + 7   = 22

Ö 9   +  7  = 22

5 (3)  +  7  = 22

15 + 7  = 22 


4) 3a3   = 81

Solution:

Divide both sides by 3:

a3   = 27

Change both sides to same base, recognizing: 3 3   = 27

Then: a3   =   33   

a =  3

Check from original eqn.

3a3   = 81

3(3)3   = 81

3 (27)  = 81 


5) 4x = 8 x+1

Solution:

Rem: same base exponents can be equated

Note: 4  = 2 2     and:  8 = 2 3

Rewrite eqn. for the same base:

2 2x = 3(x+1)

Equate exponents:

2x  =   3x  +3

Solve for x:  x  = -3

x  = -3

Check in original eqn.

4(-3) = 8 (-3+1)

4(-3) = 8 -2

0.16   =   0.16


6) b-5 = 1/32

Solution:

1/5  =   1/32

1/b 5  =   1/2 5  (Same base)

Þ   b  = 2 

 Check in original eqn.

2 =   32  so:  2 -5  =    1/32

From exponent rule:     a -n  =  1/a n
 
7)  3 +   7 x-1  =  10

Solution:

Isolate exponent member:
 
 7 x-1  =  10  - 3  = 7

Use same base to set exps equal:

7 x-1  =    7

By rules of exponents:   a 1  =   a

So:   7 =  7 1

Set exps equal:  x- 1 = 1  so x = 2

Check using original eqn.

 3 +   7 2 -1  =  10

3 +  7 1    =   10

3 +  7    =   10


For each of the following, write as a power with positive exponents in simplest form:

8)

Solution:  By properties of exponents:

 a m/ n     =   (a 1/n ) m     = (a m) 1/n

Þ

½ (18 a 6  2) 1/2

=  ½ (3Ö2  a 3  b) =  3Ö2  a 3  b/ 2

9)

Solution:  By properties of exponents:

( n Ö a ) m     =   n Ö( a m )  =  (a 1/n ) m 

Þ  

[9 1/5  ] 4 =  9 4/5   = 5.3

10)

Solution:  By properties of exponents:

( n Ö a ) m     =   n Ö( a m )  =  (a 1/n ) m 

Þ
(w 15  x 20 y -5 )  1/10

=  (w 15/10  x 20/10 y -5/10 )

 =  w 3/2  x y -1/2 



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