The Problem:
Consider the solar half-sphere and the energy going into it each second. We know on average photons are absorbed after traveling a distance with optical depth t =1 in the propagation direction. Averaged over all directions this corresponds to a vertical optical depth of t = 2/3. Based on this find:
a) The energy going into the half sphere each second.
Solution:
This is just: s(Teff)4 = p F = D 2p S =D 2p I
b) The change in (a) over each absorption and re-emission over vertical optical depth.
Solution:
Over a vertical optical depth one has t = 2/3, then:
D 2p S/D t = p F/ (2/3) = 3p F/ 2
or:
DS/D t = 3p F/ 2 (2p) = 3F/4
c) The total absorption and total emission and the relationship between them, defined over all space.
Solution:
Over all space, the total emission = 4p S and the total absorption = 4p J, and by radiative equilibrium: 4p S = 4p J so that S = J.
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