Solution To Simple Linear Algebra Problem (3)

Solution: 

We obtain the spanning vectors here by taking differences. 

So, let: A = (1, 1), B = (2, -1) and C = (4, 6). 

Then:

B - A = [(2 - 1), (-1 -1)] = (1, -2)

C - B = [(4 - 2), (6 - (-1)] = (2, 7)

Then: the matrix is:

M =

(1....-2)
(2.....7)

So Det (M)

= (1 x 7) - [(-2) x 2]

= 7 - (-4) = 7 + 4 = 11 sq. units.