Wednesday, April 1, 2026

Solution to Mensa Circle With Analytic Geometry Problem

 

The general equation of a circle is:


 (x - a) 2 -  (y - b) 2 =  r 2

Where (a, b) denotes the coordinate of the center, and r is the radius. See e.g.


For the circle in the problem, defined by:

(x - 132) 2 -  (y - 132) 2 = 24, 649  

The center is at:  (132, 132)  and the radius is:

Ö 24, 649   =    157

Then:  AO =  157

But the horizontal distance from A to O (see reconstructed diagram) is 132.

By the Pythagorean theorem:

(Vertical distance from A to O)2    + (132) 2 =   (157) 2     = 7, 225


Then:  Vertical distance from A to O  =   Ö 7, 225  =  85

Now,  <ACM  and  < ACN  are inscribed angles with both =  p/4  radians

The inscribed angle theorem states:

An inscribed angle is equal to one half the central angle that intercepts the same arc.

Therefore:  <ACM  =  ½  < AOM

And:  <ACN = ½  < AOM   +   < AOM

=  <AON  =    p/2  radians

NM is a diameter (in the reconstructed circle) since <AON and <AOM are on opposite sides of  AO  and < AOM + < AON =  p   radians

NM is perpendicular to AO, since < AOM and < AON are p/2  radians relative to AO.

Then:  The slope of AC =  85/ 132

The slope of NM =  132/ 85

M coordinates are: (132 + 85, 132 + 132) = (217, 264)

N coordinates are: (132 - 85, 132 - 132) = (47, 0)